Project Euler in F#: Problem 8

Find the greatest product of five consecutive digits in the 1000-digit number.

module Problem8 =
    let input =
        "73167176531330624919225119674426574742355349194934
        96983520312774506326239578318016984801869478851843
        85861560789112949495459501737958331952853208805511
        12540698747158523863050715693290963295227443043557
        66896648950445244523161731856403098711121722383113
        62229893423380308135336276614282806444486645238749
        30358907296290491560440772390713810515859307960866
        70172427121883998797908792274921901699720888093776
        65727333001053367881220235421809751254540594752243
        52584907711670556013604839586446706324415722155397
        53697817977846174064955149290862569321978468622482
        83972241375657056057490261407972968652414535100474
        82166370484403199890008895243450658541227588666881
        16427171479924442928230863465674813919123162824586
        17866458359124566529476545682848912883142607690042
        24219022671055626321111109370544217506941658960408
        07198403850962455444362981230987879927244284909188
        84580156166097919133875499200524063689912560717606
        05886116467109405077541002256983155200055935729725
        71636269561882670428252483600823257530420752963450"

    let ans = seq {for c in input -> int(c) - int '0'} |> Seq.windowed 5 |> Seq.map (Array.reduce (*)) |> Seq.max

F#’s nice sequence methods made short work of this problem. I wrote this as a sequence comprehension, just because I thought it was neat that you can treat a string as a sequence of characters, but (and perhaps my Ruby background is showing) I think it would have been clearer to do the conversion using a map (Seq.map (Char.GetNumericValue >> int)). And just as a note to myself, this was fast enough that there wasn’t any point in using Seq.cache, but I might want to make use of that in the future, as problems get bigger.

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Project Euler in F#: Problem 8

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